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<title>Comments on: Solar Calculator Tutorial</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html</link>
<description></description>
<lastBuildDate>Tue, 22 May 2012 02:52:02 -0700</lastBuildDate>
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<dc:date>Tue, 22 May 2012 02:52:02 -0700</dc:date>
<item>
<title>By: Zakir</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-278</link>
<dc:creator>Zakir</dc:creator>
<pubDate>Thu, 29 Mar 2012 04:56:15 -0700</pubDate>
<description>

	1 Amp AC = 10 Amps DC …. you have written this for 110 Volts AC ….. what will be the conversion factor if we are on 220 Volts AC ??? </description>
<content:encoded><![CDATA[<p>1 Amp AC = 10 Amps DC &#8230;. you have written this for 110 Volts AC &#8230;.. what will be the conversion factor if we are on 220 Volts AC ??? </p>]]></content:encoded>
</item>
<item>
<title>By: Tech</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-279</link>
<dc:creator>Tech</dc:creator>
<pubDate>Thu, 29 Mar 2012 08:37:59 -0700</pubDate>
<description>

	1 AMP AC x 110 Volts AC = ~110 Watts. 110 Watts divided by 12 Volts DC will give you ~10 (9.1) AMPS DC. Volts x Amps = Watts. Therefore, 1 AMP AC x 220 Volts AC = 220 Watts. 220 Watts divided by 12 Volts DC will give you ~20 (18.3) AMPS DC. </description>
<content:encoded><![CDATA[<p>1 <span class="caps">AMP</span> AC x 110 Volts AC = ~110 Watts. 110 Watts divided by 12 Volts DC will give you ~10 (9.1) <span class="caps">AMPS</span> DC. Volts x Amps = Watts. Therefore, 1 <span class="caps">AMP</span> AC x 220 Volts AC = 220 Watts. 220 Watts divided by 12 Volts DC will give you ~20 (18.3) <span class="caps">AMPS</span> DC. </p>]]></content:encoded>
</item>
<item>
<title>By: Duke</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-300</link>
<dc:creator>Duke</dc:creator>
<pubDate>Wed, 11 Apr 2012 23:30:19 -0700</pubDate>
<description>

	Your example calculation converting AC amps to DC Watts adding 10% for inverter inefficiency escaped me. 
 10% of 2AC amps = 0.4DC amps? Shouldn‘t this be 0.2DC amps added to 20DC amps (20.2 amps)? 
 So 2AC amps=242.4DC watts. Did you mean to use a 20% inefficency adder instead?  

	1 Amp AC = 10 Amps DC. (example, 2AC amps =20DC amp) 

	Add 10% (20.4 amps) 

	DC amps x 12v = DC watts. (20.4 ×12 =244.8 watts)</description>
<content:encoded><![CDATA[<p>Your example calculation converting AC amps to DC Watts adding 10% for inverter inefficiency escaped me.  <br />
10% of 2AC amps = 0.4DC amps?  Shouldn&#8216;t this be 0.2DC amps added to 20DC amps (20.2 amps)? <br />
So 2AC amps=242.4DC watts. Did you mean to use a 20% inefficency adder instead?   </p>

	<p>1 Amp AC = 10 Amps DC. (example, 2AC amps =20DC amp)</p>

	<p>Add 10% (20.4 amps)</p>

	<p>DC amps x 12v = DC watts. (20.4 &#215;12 =244.8 watts)</p>]]></content:encoded>
</item>
<item>
<title>By: Tech</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-308</link>
<dc:creator>Tech</dc:creator>
<pubDate>Fri, 13 Apr 2012 09:21:34 -0700</pubDate>
<description>

	You are correct, the numbers in the example are incorrect. 2 Amps AC x 120 Volts AC = 240 Watts. 240 Watts / 12 volts DC = 20 Amps DC. 10% of 20 Amps DC is 2 Amps DC. 20 Amps DC + 2 Amps DC = 22 Amps DC. The final Wattage rating, given the 10% inefficiency rate, should be: 264 Watts.</description>
<content:encoded><![CDATA[<p>You are correct, the numbers in the example are incorrect. 2 Amps AC x 120 Volts AC = 240 Watts. 240 Watts / 12 volts DC = 20 Amps DC. 10% of 20 Amps DC is 2 Amps DC. 20 Amps DC + 2 Amps DC = 22 Amps DC. The final Wattage rating, given the 10% inefficiency rate, should be: 264 Watts.</p>]]></content:encoded>
</item>
<item>
<title>By: ajmera</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-339</link>
<dc:creator>ajmera</dc:creator>
<pubDate>Tue, 01 May 2012 21:08:23 -0700</pubDate>
<description>

	hi there,
 i have a battery with specs 12V 7.0AH Cycle use 14.5-14.9V stand by use 13.6-13.8 and initial current is less than 2.8A..
 And i am having a solar panel is of 12V 4W…
 How can i charge the battery with this solar panel?
 How much time it will take to charge the battery?
 I am running 100LED‘s of 3.5V 20mA?
 Please suggest me how the thing will work because i need the bed should be able to work even in nights mmm its almost 15 hours a day i want the led turned on…
 Appreciate your help….
 thank you </description>
<content:encoded><![CDATA[<p>hi there,<br />
i have a battery with specs 12V 7.0AH Cycle use 14.5-14.9V stand by use 13.6-13.8 and initial current is less than 2.8A..<br />
And i am having a solar panel is of 12V 4W&#8230;<br />
How can i charge the battery with this solar panel?<br />
How much time it will take to charge the battery?<br />
I am running 100LED&#8216;s of 3.5V 20mA?<br />
Please suggest me how the thing will work because i need the bed should be able to work even in nights mmm its almost 15 hours a day i want the led turned on&#8230;<br />
Appreciate your help&#8230;.<br />
thank you </p>]]></content:encoded>
</item>
<item>
<title>By: Tech</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-340</link>
<dc:creator>Tech</dc:creator>
<pubDate>Wed, 02 May 2012 11:39:49 -0700</pubDate>
<description>

	A 4 Watt panel will deliver roughly 300 mAh of charge an hour, in direct sunlight. Connect the positive and negative output cables from the panel to the matching terminals on the battery to charge it. With a rate of 0.3 Amps, it would take approximately 25 hours to fully charge from a discharged state. This is roughly 4 days worth of sunlight (6-7 hours a day). Your LED lights are rated for 3.5 volts, your power source is 12 volts. You need to match up the voltages, it‘s important to keep the system the same. After you accomplish that, please us our other online calculators to help you determine either a proper size battery, or load runtime.</description>
<content:encoded><![CDATA[<p>A 4 Watt panel will deliver roughly 300 mAh of charge an hour, in direct sunlight. Connect the positive and negative output cables from the panel to the matching terminals on the battery to charge it. With a rate of 0.3 Amps, it would take approximately 25 hours to fully charge from a discharged state. This is roughly 4 days worth of sunlight (6-7 hours a day). Your <span class="caps">LED</span> lights are rated for 3.5 volts, your power source is 12 volts. You need to match up the voltages, it&#8216;s important to keep the system the same. After you accomplish that, please us our other online calculators to help you determine either a proper size battery, or load runtime.</p>]]></content:encoded>
</item>
<item>
<title>By: ajmera</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-341</link>
<dc:creator>ajmera</dc:creator>
<pubDate>Wed, 02 May 2012 22:24:47 -0700</pubDate>
<description>

	ok thanks a lot i will let you know if it works!!!</description>
<content:encoded><![CDATA[<p>ok thanks a lot i will let you know if it works!!!</p>]]></content:encoded>
</item>
<item>
<title>By: HPC</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-361</link>
<dc:creator>HPC</dc:creator>
<pubDate>Thu, 10 May 2012 04:02:03 -0700</pubDate>
<description>

	Hi, interested in learning more about solar power, and that\‘s how I found you….. I\‘ve been doing some research in alternative ways of getting myself around other than gas vehicles… well, I found something that uses a 78v 20ah battery, my question is, if i had a solar panel battery charging setup that had output amps of 5a, would it still be 4hrs or so? does the size in volts makes a difference in charge times?</description>
<content:encoded><![CDATA[<p>Hi, interested in learning more about solar power, and that\\\&#8216;s how I found you&#8230;.. I\\\&#8216;ve been doing some research in alternative ways of getting myself around other than gas vehicles&#8230; well, I found something that uses a 78v 20ah battery, my question is, if i had a solar panel battery charging setup that had output amps of 5a, would it still be 4hrs or so? does the size in volts makes a difference in charge times?</p>]]></content:encoded>
</item>
<item>
<title>By: Tech</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-363</link>
<dc:creator>Tech</dc:creator>
<pubDate>Thu, 10 May 2012 09:04:47 -0700</pubDate>
<description>

	If you have a 72 volt battery system, you will need 72 volt solar system. Like batteries, this will require wiring in series a total of at least six 12 volt solar panels to make it work. If you need 5 Amps of output, you‘re look at least 360 Watts of total solar power. Since your battery bank capacity is 20 AH, 4 hours is a good estimate.</description>
<content:encoded><![CDATA[<p>If you have a 72 volt battery system, you will need 72 volt solar system. Like batteries, this will require wiring in series a total of at least six 12 volt solar panels to make it work. If you need 5 Amps of output, you&#8216;re look at least 360 Watts of total solar power. Since your battery bank capacity is 20 AH, 4 hours is a good estimate.</p>]]></content:encoded>
</item>
<item>
<title>By: Asad</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-367</link>
<dc:creator>Asad</dc:creator>
<pubDate>Wed, 16 May 2012 03:34:06 -0700</pubDate>
<description>

	Hi, I have 4 solar panels 130 watt each, 2 in series. My battery and inverter system is 24 volt. at peak it produces 8.2-8.4 amperes. I have two 180 ampere batteries in series. Solar panels charge the consumed battery in 2-4 hours. The rest of the day the house runs on direct out put saving the battery current for the night. The question is how much energy can I spend at day time without any loss from batteries.</description>
<content:encoded><![CDATA[<p>Hi, I have 4 solar panels 130 watt each, 2 in series. My battery and inverter system is 24 volt. at peak it produces 8.2-8.4 amperes. I have two 180 ampere batteries in series. Solar panels charge the consumed battery in 2-4 hours. The rest of the day the house runs on direct out put saving the battery current for the night. The question is how much energy can I spend at day time without any loss from batteries.</p>]]></content:encoded>
</item>
<item>
<title>By: Asad</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-368</link>
<dc:creator>Asad</dc:creator>
<pubDate>Wed, 16 May 2012 03:37:10 -0700</pubDate>
<description>

	I have four 130 watt solar panels 2 in series, 24 volts battery and inverter system, 180×2 ampere batteries in series. at peak, the system produces 8.0-8.4 amperes. The question is how much energy can I consume directly saving the battery energy for the night. </description>
<content:encoded><![CDATA[<p>I have four 130 watt solar panels 2 in series, 24 volts battery and inverter system, 180&#215;2 ampere batteries in series. at peak, the system produces 8.0-8.4 amperes. The question is how much energy can I consume directly saving the battery energy for the night. </p>]]></content:encoded>
</item>
<item>
<title>By: Tech</title>
<link>http://www.site.com/articles//kb/solar-calculator-tutorial.html#comment-372</link>
<dc:creator>Tech</dc:creator>
<pubDate>Wed, 16 May 2012 14:41:15 -0700</pubDate>
<description>

	How many hours of sunlight do you have left over after the batteries have been recharged? Are you going to run your house directly off the solar panels during the daytime?</description>
<content:encoded><![CDATA[<p>How many hours of sunlight do you have left over after the batteries have been recharged? Are you going to run your house directly off the solar panels during the daytime?</p>]]></content:encoded>
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